X 2Y 4 3X Y 5. Transcript Ex 63 12 Solve the following system of inequalities graphically x – 2y ≤ 3 3x + 4y ≥ 12 x ≥ 0 y ≥ 1 First we solve x – 2y ≥ 3 Lets first draw graph of x – 2y = 3 Putting x = 0 in (1) 0 – 2y = 3 −2y = 3 y = ( 3)/( −2) y = –15 Putting y = 0 in (1) x – 2(0) = 3 x – 0 = 3 x = 3 Drawing graph Checking for (00) Putting x = 0 y = 0 x – 2y ≤ 3 0 2.
PDF file1 y = 4 x + 2 2 y = 5 – 2x 3 2y = 3x – 8 4 6y – 5x = 0 5 3 1 x – 8 3 y = 11 6 x = 4y + 7 State whether the graphs of the following equations are parallel perpendicular or neither 7 9 11 13 Name_____ Date_____ Class_____ x + y = 5 x + y = –10 y = 2x y = 2x – 4 3x – 8y = 11 3x – 6y = 10 3 1 x + 3 2 y = 5 3.
1. Solve the system using elimination. 3x+3y=27 x3y=11 a
3x+2y=17 2x+5y=26 a (34)*** b (211/2) c (1/25) d (17) 5 Solve the system using elimination 5x9y=43 3x+8y=68 a (1/367/8) is inconsistent enter INCONSISTENT If the system has infinitely many solutions show a general solution in terms of x y or z) x + 2y − z math Use elimination to solve each system of equations x+y=3 2x3y=16 math Solve the.
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So everywhere we see an x we can substitute it with a y minus 4 So let’s do that So if we substitute y minus 4 for x in this top equation the top equation becomes 2y is equal to instead of an x the second constraint tells us that x needs to be equal to y minus 4 So instead of an x we’ll write a y minus 4 and then we have a plus 7 All I.
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3x+2y=12x+y=5 In order to solve by elimination coefficients of one of the variables must be the same in both equations so that the variable will cancel out when one equation is subtracted from the other 3x+2y=123x+3y=3\times 5 To make 3x and x equal multiply all terms on each side of the first equation by 1 and all terms on each side of the second by 3 3x+2y=123x+3y=15 .